Yahoo Answers: Answers and Comments for How do I finish this math problem? [Mathematics]
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enGB
Sun, 14 Jul 2019 18:54:01 +0000
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Yahoo Answers: Answers and Comments for How do I finish this math problem? [Mathematics]
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From l: 7 is the answer
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Mon, 15 Jul 2019 22:19:41 +0000
7 is the answer

From Puzzling: The easiest way to solve that is to iterativel...
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Sun, 14 Jul 2019 19:47:28 +0000
The easiest way to solve that is to iteratively try larger values of n, rather than trying to "solve" that complicated inequality.
You know you are looking for an integer, so try some guesses. You can even narrow it down using a binary search.
You'll find that 22 is one one side of the boundary and 23 is on the other. So the answer is 23 people.
I treated it as an equality and gave the problem to WolframAlpha and it came back with:
n ≈ 22.7676903156182
But you can't have a fraction of a person so round up to 23 people.

From Dixon: You have done the hard work but you can't ...
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Mon, 15 Jul 2019 04:18:25 +0000
You have done the hard work but you can't solve that equation algebraically, it just needs trial and error.
Note that since you are looking for an integer solution it is not one of these iterative solutions where you just get endless decimal places. You will find one integer gives below 0.5 and the next gives above 0.5

From Mike G: The Probability of having at least 2 sharing a...
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Sun, 14 Jul 2019 23:29:52 +0000
The Probability of having at least 2 sharing a birthday in a group of n people
Your method is correct and if you continued you would end up with (for exactly P = 0.5)
P = 1  nPr(365,n)/365^n= 0.5
when n = 23
P = 1nPr(365,23)/365^23
P = 0.507 = 50.7%

From Barkley Hound: Rather that repeat it here look at this page.
...
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Sun, 14 Jul 2019 19:04:12 +0000
Rather that repeat it here look at this page.
https://brownmath.com/stat/birthday.htm