Yahoo Answers: Answers and Comments for How many ways can 1 2 3 5 5 8 be arranged and how many of these numbers could be divided by 15? [Mathematics]
Copyright © Yahoo! Inc. All rights reserved.
https://uk.answers.yahoo.com/question/index?qid=20090101173838AAQIyiO
From Anonymous
enGB
Thu, 01 Jan 2009 17:38:38 +0000
3
Yahoo Answers: Answers and Comments for How many ways can 1 2 3 5 5 8 be arranged and how many of these numbers could be divided by 15? [Mathematics]
292
38
https://uk.answers.yahoo.com/question/index?qid=20090101173838AAQIyiO
https://s.yimg.com/zz/combo?images/emaillogouk.png

From Pi R Squared: Hi,
In order to be divisible by 15, a numbe...
https://uk.answers.yahoo.com/question/index?qid=20090101173838AAQIyiO
https://uk.answers.yahoo.com/question/index?qid=20090101173838AAQIyiO
Thu, 01 Jan 2009 17:48:07 +0000
Hi,
In order to be divisible by 15, a number must end in either 5 or 0, and the sum of all its digits must be divisible by 3. Since 0 was not included in the numbers to be arranged, then 5 must be in the last position. That leaves the other 5 digits to be arranged in 5! ways. This makes 120 distinguishable arrangements of those 6 digits.
120 ways <==ANSWER
I hope that helps!! :)

From M3: a) the number can be arranged in 6!/2! = 360 w...
https://uk.answers.yahoo.com/question/index?qid=20090101173838AAQIyiO
https://uk.answers.yahoo.com/question/index?qid=20090101173838AAQIyiO
Thu, 01 Jan 2009 17:47:22 +0000
a) the number can be arranged in 6!/2! = 360 ways
b) all numbers ending with 5 will also be divisible by 15
so they will number (2/6)*360 = 120

From I Don't Eat Vodka: I think they can be arranged 6! different ways.
https://uk.answers.yahoo.com/question/index?qid=20090101173838AAQIyiO
https://uk.answers.yahoo.com/question/index?qid=20090101173838AAQIyiO
Thu, 01 Jan 2009 17:46:57 +0000
I think they can be arranged 6! different ways.

From RandomNormality: To figure out how many ways it can be arranged...
https://uk.answers.yahoo.com/question/index?qid=20090101173838AAQIyiO
https://uk.answers.yahoo.com/question/index?qid=20090101173838AAQIyiO
Thu, 01 Jan 2009 17:44:13 +0000
To figure out how many ways it can be arranged, it's just 6!. However, since 5 appears twice, it is 6!/2! or 360.
In order for it to be divisible by 15, the last digit has to equal 5 (since 1+2+3+5+5+8=24, and that's already divisible by 3)
From the rest of the digits, it's just 5! or 120.

From xxralliexx: well the answer to the first question is.....f...
https://uk.answers.yahoo.com/question/index?qid=20090101173838AAQIyiO
https://uk.answers.yahoo.com/question/index?qid=20090101173838AAQIyiO
Thu, 01 Jan 2009 17:43:44 +0000
well the answer to the first question is.....first you must use a permutation or a combinattion(sorry i forgot which ones which)....which is where you do 1*2*3*4*5*6 because there are six numbers... the second one....ya gotta figure it out!

From Anonymous: all i know is that they can be arranged in 36 ...
https://uk.answers.yahoo.com/question/index?qid=20090101173838AAQIyiO
https://uk.answers.yahoo.com/question/index?qid=20090101173838AAQIyiO
Thu, 01 Jan 2009 17:43:20 +0000
all i know is that they can be arranged in 36 ways.
i think;;