Find the emf generated.?

A shunt generator supplies a load of 5,500 W at 110 V through a pair of feeder conductors having a resistance of 0.02 ohm each. The armature, shunt field resistances are 0.15 ohm and 50 ohms, respectively.           

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  • 1 month ago

    We know the voltage at the load = 110V

    We know V*I = 5500 so I into the load = 5500/110 = 50A

    Therefore the voltage drop over the feeder conductors = 50*(0.02+0.02) = 2V

    Thus the voltage across the shunt field = 110+2 = 112V

    The current into the shunt field = 112/50Ω = 2.24A

    By KCL the current leaving the armature = 50+2.24 = 52.24A

    Therefore 112 = emf - 52.24*0.15Ω

    emf = 112 + 52.24*0.15Ω = 119.836V or about 120V

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