# Find the emf generated.?

A shunt generator supplies a load of 5,500 W at 110 V through a pair of feeder conductors having a resistance of 0.02 ohm each. The armature, shunt field resistances are 0.15 ohm and 50 ohms, respectively.

### 1 Answer

Relevance

- oldschoolLv 71 month ago
We know the voltage at the load = 110V

We know V*I = 5500 so I into the load = 5500/110 = 50A

Therefore the voltage drop over the feeder conductors = 50*(0.02+0.02) = 2V

Thus the voltage across the shunt field = 110+2 = 112V

The current into the shunt field = 112/50Ω = 2.24A

By KCL the current leaving the armature = 50+2.24 = 52.24A

Therefore 112 = emf - 52.24*0.15Ω

emf = 112 + 52.24*0.15Ω = 119.836V or about 120V

Still have questions? Get answers by asking now.