Anonymous

# Graphing help?

How can h(x)=(x+4)² can be be graphed.

### 1 Answer

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- MichaelLv 74 weeks ago
The same way as

y = (x + 4)²

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The vertex form of a parabola is

y = (x - h)² + k

Where (h, k) is the vertex

Therefor the vertex is

(-4, 0)

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Pick two values of x equadistant from the vertex

I want one of them to be x = 0 so I get the y-intercept

Therefor the other is -8

x = {-8, 0}

y = (-8 + 4)² = 16

point (-8, 16)

y = (0 + 4)² = 16

point (0, 16)

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Now we have three points of a parabola;

plot them and draw in the curve.

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