Anonymous
Anonymous asked in Education & ReferenceHomework Help · 4 weeks ago

Graphing help?

How can h(x)=(x+4)² can be be graphed. 

1 Answer

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  • 4 weeks ago

    The same way as

    y = (x + 4)² 

    ---------------------

    The vertex form of a parabola is 

    y = (x - h)² + k

    Where (h, k) is the vertex

    Therefor the vertex is

    (-4, 0)

    ---------------

    Pick two values of x equadistant from the vertex

    I want one of them to be x = 0 so I get the y-intercept

    Therefor the other is -8

    x = {-8, 0}

    y = (-8 + 4)² = 16

    point (-8, 16)

    y = (0 + 4)² = 16 

    point (0, 16)

    ---------------------

    Now we have three points of a parabola;

    plot them and draw in the curve.

     

    Attachment image
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