Anonymous
Anonymous asked in Science & MathematicsPhysics · 1 month ago

A box sits at rest on a 29 degree slope. If the box weighs 38 Kg, what must the force of friction be to keep the box from moving? ?

2 Answers

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  • oubaas
    Lv 7
    1 month ago

    FF = -GF = -(38*-9.806*sin 29) = 180 N (2 sign. digits)

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  • NCS
    Lv 7
    1 month ago

    f = m*g*sinΘ = 38kg * 9.8m/s² * sin29º = 180 N

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