# Vertical Projectile?

I have a object whose angle is 83 degrees and initial speed is 25 m/s. How can I find the maximum height, range, and time. Thank you for helping me out.

### 1 Answer

Relevance

- oubaasLv 71 month ago
max height H :

H = (Vo*sin Θo)^2/2g = (25*0.9925)^2/19.612 = 31.4 m

time tup to get H :

tup = Vo*sin Θo/g = 25*0.9925/9.806 = 2.53 sec

total flying time t = 2*tup = 5.06 sec

range R :

R = Vo*cos Θo*t = 25*0.122*5.06 = 15.4 m

R = Vo^2/g*sin (83*2) = 25^2/9.806*0.242 = 15.4 m

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