How many liters of a 5.75 MKNO3 solution can be prepared from 51.1 g of KNO3?

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  • david
    Lv 7
    1 month ago

    molar mass = 101  ....  51.1 / 101  =  0.50594 mol

    0.50594 / 5.75  =  0.0879897 L ... round for sig figs

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