Anonymous
Anonymous asked in Science & MathematicsChemistry · 1 month ago

chem help?

A balloon whose volume is 5.0 L contains 6.1 g of N2. What mass of N2 must be added to the balloon to expand its volume to 11 L at the same temperature and pressure?

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  • Dr W
    Lv 7
    1 month ago
    Favourite answer

    ideal gas law

    .. P1V1 / (n1T1) = P2V2 / (n2T2)

    since P and T are constant.. P1=P2 and T1=T2 so they drop out

    .. V1 / n1 = V2 / n2

    since n = mass / mw and since it's all N2 here

    .. V1 / (m1/mw) = V2 / (m2/mw)

    .. V1 / m1 = V2 / m2

    .. m2 = m1 * (V2 /  V1)

    and we want mass added = m2 - m1, 

    .. mass added = m2 - m1 = m1 * (V2 / v1) - m1

    .. .. .. .... ... ..... = m1 * (V2/V1 - 1) = 6.1g * (11L / 5.0L - 1) = 7.3g

  • 4 weeks ago

    A solution containing equal masses of glycerol ( C8H8O3) and water has a density of 1.10g/mol. Calculate the following.

    A. Modality of glycerol in the solution

    B. Mole fraction of glycerol in the solution

    C. Molarity of glycerol in the solution

    With solutions please.

  • 1 month ago

    (6.1 g N2) x (11 L / 5.0 L) = 13.42 g N2 total

    (13.42 g total) - (6.1 g initially) = 7.3 g N2 to be added

  • Anonymous
    1 month ago

    I don't think that's it

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  • KennyB
    Lv 7
    1 month ago

    We can reduce the ideal gas law elation to just the ration of moles and volume -- and since the mass of a mole of N2 is also c instant. we can remove mopes and replace it with grams.  Then V1/g1 =V2/g2 and solve for g2

    g2 = (6.1 g)11L/5L.

    I get 13 g (to two significant figures)

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