Ash asked in Science & MathematicsChemistry · 3 weeks ago

chemistry ?

How much water (mL) must be added to a 0.723 M solution of lithium carbonate with a volume of 17.7 mL so that the final concentration is 0.138 M? (Give your answer to 3 significant figures?

Update:

A titration of 25.00 mL of HCl of unknown molarity required 36.50 mL of 0.1250 M NaOH to neutralise. The concentration of the unknown HCl solution = ____________M

1 Answer

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  • 3 weeks ago

    0.723 M means 0.723 mole/liter

    0.723 mole/liter x 0.0177 L = 0.01280 mol, amount in the original solution

    you want 

    0.138 M or 0.138 mol/liter

    amount of substance is unchanged as you are adding only water...

    0.01280 mol / 0.138 mol/liter = 0.0927 liter or 92.7 mL total

    you already have 17.7, so water added is 92.7 – 17.7 = 75.0 mL

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