# A cylindrical conductor has resistance of R0 = 760 Ω. It has length L, radius of the cross section r, and resistivity ρ.?

If the radius of the conductors increased by a factor of 3, what would be the value of the new resistance, in ohms?

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- AshLv 74 weeks ago
R₁ = ρL/A₁ ...(1)

R₂ = ρL/A₂ ...(1)

Dividing (1) by (2)

R₁/R₂ = A₂/A₁

R₂ = R₁A₁/A₂

R₂ = R₁(𝜋r₁²)/(𝜋r₂²)

R₂ = R₁r₁²/r₂²

Given r₂ = 3r₁, then we get

R₂ = R₁r₁²/(3r₁)²

R₂ = R₁/9

R₂ = (760 Ω)/9

R₂ = 84.4 Ω

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