A cylindrical conductor has resistance of R0 = 760 Ω. It has length L, radius of the cross section r, and resistivity ρ.?

 If the radius of the conductors increased by a factor of 3, what would be the value of the new resistance, in ohms? 

3 Answers

Relevance
  • 4 weeks ago

    A1=pi*r^2=760

    A2=pi*3r^2=760/3^2=760/9=84.44...ohms.

  • oubaas
    Lv 7
    4 weeks ago

    R' = R/(3^2) = 760/9 = 84.4 ohm 

  • Ash
    Lv 7
    4 weeks ago

    R₁ = ρL/A₁ ...(1)

    R₂ = ρL/A₂ ...(1)

    Dividing (1) by (2)

    R₁/R₂ = A₂/A₁

    R₂ = R₁A₁/A₂

    R₂ = R₁(𝜋r₁²)/(𝜋r₂²)

    R₂ = R₁r₁²/r₂²

    Given r₂ = 3r₁, then we get

    R₂ = R₁r₁²/(3r₁)²

    R₂ = R₁/9

    R₂ = (760 Ω)/9

    R₂ = 84.4 Ω

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