An empty airplane, whose mass is 120,000 [kg] has a take of acceleration of 2.0 [m/s2].?

a) What is the force acting on the plane?

b) What is the velocity of the plane at the end of a 1000 [ft] runway?

c) How long does it take for the plane to reach the end of the runway?

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  • 1 month ago
    Favourite answer

    a) What is the force acting on the plane?

    a = acceleration = 2.0 m/s²

    m = mass = 120,000 kg

    F = force = to be determined

    F = ma

    F = (120,000 kg)(2.0 m/s²)

    F = 240,000 N = 240 kN

    b) What is the velocity of the plane at the end of a 1000 [ft] runway?

    NOTE: I am going to assume that you actually mean a 1,000 m runway for two reasons:

    (1) All of the other units in the problem are metric units rather than U.S. customary

    units. (2) A 1,000 ft runway isn't really practical for any aircraft of the indicated mass.

    Actually, a 1,000 m runway is too small for a 120,000 kg aircraft, as well.

    Δx = runway length = 1,000 m

    v0 = initial veocity = 0 m/s

    a = acceleration = 2.0 m/s²

    v = final velocity = to be determined

    v² = (v0)² + 2aΔx

    v² = (0 m/s)² + 2(2.0 m/s²)(1,000 m)

    v² = 4,000 m²/s²

    v = √( 4,000 m²/s²)

    v = 63.2455532 m/s = 63.2 m/s

    c) How long does it take for the plane to reach the end of the runway?

    See the above NOTE.

    v = v0 + at

    v - v0 = at

    (v - v0) / a = t

    t = (v - v0) / a

    t = (63.2 m/s - 0 m/s) / 2.0 m/s²

    t = 31.6227766 s = 31.6 s

  • oubaas
    Lv 7
    1 month ago

    a) What is the force F acting on the plane?

    F = m*a = 1.2*10^5*2 = 2.4*10^5 N

    b) What is the velocity V of the plane at the end of a L = 1000 [ft] runway?

    V = √ 2*a*L = √ 2*2*1000*0.3048 = 35 m/sec (just two sign. digits)

    c) How long t does it take for the plane to reach the end of the runway?

    2d = V*t

    t = 2d/V = 610/35 = 17 sec (just two sign. digits)

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