How many ions are in 15g of ammonium carbonate((NH4)2CO3)?

How do you calculate this? Please explain it to me.

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  • KennyB
    Lv 7
    1 month ago
    Favourite answer

    First, determine moles:  divide 15 g by the molecular weight of (NH4)2CO3.   This is about 96 g/mole.

    Now, to get ions, work out the ionization equation:

    (NH4)2CO3 --> 2NH4+ + CO3-2

    So, for every mole of the compound, you produce three moles of ions

    Voila

  • 1 month ago

    (NH4)2CO3 → 2 NH4{+} + CO3{2-}   [three ions total]

    (15 g (NH4)2CO3) / (96.0858 g (NH4)2CO3/mol) ×

    (3 mol ions / 1 mol (NH4)2CO3) × (6.022 × 10^23 ions/mol) = 2.8 × 10^23 ions

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