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- PhilipLv 61 month ago
38 = AD = AB+BC+CD = 2x+2 +10 + 2x+2 = 10 + 2(2x+2);

2(2x+2) = 38-10 = 28;

(2x+2) = CD = 14.

- KrishnamurthyLv 71 month ago
The length of CD if AD = 38:

AD = AB + BC + CD

= (2x + 2) + 10 + (2x + 2)

4x + 14 = 38

x = 6

CD = 14

- DavidLv 71 month ago
If 2x+2+10+2x+2x+2 = 38 then 4x+14 = 38 and solving the equation x = 6

Therefore length CD: (2*6)+2 = 14

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- 1 month ago
What is the length of BE? 3 BE. 4ī ... If CD = 4, CA = 6, and BC = 9, find. CE ... If AD = 2,. DB = x - 1, AE = x, and EC = x + 2, find AE. o- (2-4)(x+1) x=4 x=-1. L x-1 ... mZWAC = 33°, mZRYX = 74º. a. MZDZW = _74". W33 11 747. 740. 38. 74. 741.

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