# Find the equation of the line that passes through the point (2, 1) and is perpendicular to y=−25x+3.?

Update:

y=(-2/5)x+3

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- rotchmLv 71 month agoFavourite answer
Given the eqs y= mx + b, what is the slope?

Then, what principle, or formula, you saw for the slope of the perpendicular to that?

Answer that (as an update in your post) & we will proceed.

- billrussell42Lv 71 month ago
y=−25x+3

has a slope of –25

perpendicular would have a slope of +1/25

so equation is

y = (1/25)x + k

use point to find k

1 = (1/25)2 + k

k = 1 – 2/25 = 25/25 – 2/25 = 23/25

so equation is

y = (1/25)x + 23/25

or

25y = x + 23

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