Anonymous
Anonymous asked in Science & MathematicsChemistry · 1 month ago

What's the structural formula of the acid? ?

A 6.1 g acid monocarboxylic acid reacts with NaHCO3 and releases 11.2 liters CO2.

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  • 1 month ago
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    Suppose the volume of CO₂ is measured at STP.

    At STP, the molar volume of CO₂ is 22.4 L/mol.

    Denote the monocarboxylic acid as RCOOH.

    RCOOH + NaHCO₃ → RCOONa + H₂O + CO₂

    Mole ratio RCOOH : CO₂ = 1 : 1

    Moles of CO₂ produced = (11.2 L) / (22.4 L/mol) = 0.5 mol

    Moles of RCOOH reacted = 0.5 mol

    Molar mass of the monocarboxylic acid = (6.1 g) / (0.5 mol) = 12.2 g/mol

    The smallest monocarboxylic acid is HCOOH, which has a molar mass of 46 g/mol.

    Hence, the question has no solution,

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