What's the structural formula of the acid? ?
A 6.1 g acid monocarboxylic acid reacts with NaHCO3 and releases 11.2 liters CO2.
- sioiengLv 71 month agoFavourite answer
Suppose the volume of CO₂ is measured at STP.
At STP, the molar volume of CO₂ is 22.4 L/mol.
Denote the monocarboxylic acid as RCOOH.
RCOOH + NaHCO₃ → RCOONa + H₂O + CO₂
Mole ratio RCOOH : CO₂ = 1 : 1
Moles of CO₂ produced = (11.2 L) / (22.4 L/mol) = 0.5 mol
Moles of RCOOH reacted = 0.5 mol
Molar mass of the monocarboxylic acid = (6.1 g) / (0.5 mol) = 12.2 g/mol
The smallest monocarboxylic acid is HCOOH, which has a molar mass of 46 g/mol.
Hence, the question has no solution,