Anonymous
Anonymous asked in Science & MathematicsPhysics · 1 month ago

Physics question?

A cork is attached to a thread and whirled horizontally in a circle of radius 60cm of a rate of 30rpm. The cork has a mass of 15g

1) what is the period of the whirling cork?

2) hence calculate the linear speed of the cork

3) determine the magnitude of the tension in the thread

2 Answers

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  • oubaas
    Lv 7
    1 month ago

    angular speed ω = n*2PI/60 = 2PI/60*30 = PI rad/sec 

    period T = 2PI/ω = 2PI/PI = 2.0 sec 

    Vt = r/T = 0.6/2 = 0.30 m/sec 

    T = m*ac = m*V^2/r = 15*10^-3*0.30^2/0.6 = 2.3 mN

  • Argent
    Lv 7
    1 month ago

    1) 30 rpm = 1/2 rps, so the period T is 1/(1/2 sˉ¹) = 2 s.

    2) The speed v is the circumference C divided by the period T.C = 2πr = 2π(0.60 m) = 1.2π m (≈ 3.8 m), so v = C/T = 0.6π m/s (≈ 1.9 m/s).

    3) The tension force F = mv²/r = (0.015 kg)(0.6π m/s)²/(0.60 m) = 0.009π² N

    (≈ 0.089 N).

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