Write an equation of a line in point-slope form that has a slope of -2 and passes through (5, -1).?

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  • 1 month ago

    Point slope form: y-y1= m(x-x1)

    Substitute in the given values:

    y-(-1) = -2*(x-5)

    y+1 = -2*(x-5)

  • 1 month ago

    y - -1 = -2(x - 5)

    y + 1 = -2x + 10 

    y = -2x + 9 

  • David
    Lv 7
    1 month ago

    Point of passage: (5, -1) 

    Slope: -2

    Equation: y - -1 = -2(x -5) => y = -2x +9

  • ?
    Lv 7
    1 month ago

    y - (-1) = -2(x - 5)..........ANS

    or

    y + 1 = -2 (x - 5)...........ANS

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  • 1 month ago

    Point slope form is

    y - y₁ = m(x - x₁)

    where m is the slope and (x₁, y₁) is a point on the line

    -------------------------

    plug in the givens

    y + 1 = -2(x - 5) <–––––––

  • 1 month ago

    y2-y1=m(x2-x1)

    m=-2

    y1= -1

    x1= 5

    y2 +1 =-2 (x2- 5)

    y = -2x +10 -1

    y= -2x +9  =>  this is your answer

    Please rate!!

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