How much heat is needed to melt 10.0 grams of ice at -10°C until it is water at 10°C?

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  • 1 month ago

    Given:

    m = 10 g

    C = 0.902 J/g.oC

    Ti = 10 oC

    Tf = -10 oC

    use:

    Q = m*C*(Tf-Ti)

    Q = 10.0*0.902*(-10.0-10.0))

    Q = ) -180J

    Answer: )-180 J

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