Complete reduction of 1 mole of (3E)-3-methylhepta-3-en 1- yne will require how many moles of hydrogen (H2)?
- micatkieLv 71 month ago
The answer: e. 3
Refer to the figure below
(3E)-3-methylhepta-3-en-1-yne has 1 C=C double bond and 1 C≡C triple bond. The C=C double bond needs 1 mole of H₂ to reduce it to C-C single bond, while the C≡C triple bond needs 2 moles of H₂ to reduce it to C-C single bond.
No. of moles of H₂ needed = (1 + 2) moles = 3 moles
Refer to the figure below.
The molecular formula of (3E)-3-methylhepta-3-en-1-yne is C₇H₁₂, while that of the reduced product is C₇H₁₈ (CₙH₂ₙ₊₂). 6 moles of H atoms are required, i.e. 3 moles of H₂.