Physics help please?
The Hubble Space Telescope orbits the Earth every 95 minutes, taking breathtaking images of our universe. Calculate its altitude above the Earth’s
- NCSLv 72 months agoFavourite answer
For "orbit", centripetal acceleration = gravitational acceleration, or
ω²r = (2π/T)²r = 4π²r / T² = v²/r = GM/r²
where the first four terms are all expressions for centripetal acceleration
and G = Newton's gravitational constant = 6.674e−11 N·m²/kg²
and M = mass of central body
and r = orbit radius
and T = period
and v = orbit velocity
4π²r / T² = GM/r²
r³ = GMT² / 4π²
r³ = 6.674e−11N·m²/kg² * 5.98e24kg * (95*60 s)² / 4π²
r³ = 3.28e28 m³
r = 6.90e6 m
altitude h = r - Re = 6.90e6m - 6.371e6m = 5.3e5 m
or 530 km
If your reference tables have a different value for the mass and/or radius of the Earth, use it.
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