A student wants to analyze a sample of 0.200 AgNO3 solution?
a. What volume of a 0.150 M HCl solution is needed to precipitate all of the silver
ions from a 15.0 mL of the solution solution?
b. What mass of KCl must be added to precipitate all of the silver ions from a 45.0
mL of the solution?
- Roger the MoleLv 71 month ago
Supposing the missing units on "0.200 AgNO3" to be "M":
AgNO3 + HCl → AgCl + HNO3 [balanced as written]
(0.200 M AgNO3) x (15.0 mL) x (1 mol HCl / 1 mol AgNO3) / (0.150 M HCl) =
20.0 mL HCl
AgNO3 + KCl → AgCl + KNO3 [balanced as written]
(0.0450 L) x (0.200 mol AgNO3/L) x (1 mol KCl / 1 mol AgNO3) x
(74.5513 g KCl/mol) = 0.671 g KCl