What is the amount of heat in kilojoules required to convert 184.0 g of ice at −15.2°C to liquid water at 35.6°C?

Answer 1

You need some constants 

 ==  The specific heat of ICE ( it is not the same as liquid water)  

  ==  The specific heat of liquid water ( 4.184 J/g deg C)

 ==  the latent heat of fusion of water

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  Q = mc(delta T)  <<<  do this calc. for ice  ... delta T will be (0 - -15.2)

  Q = m Lf  <<< melting ice

  Q = mc(delta T)   <<<  this time for liquid ice  ... delta T will be (35.6 - 0)

  final answer .. add all the above