HB asked in Science & MathematicsEngineering · 6 months ago

# A small heating coil has a constant resistance of 25 W. a) How much power would the coil consume if the voltage drop across it is 96 V?

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• 2 months ago

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• Anonymous
3 months ago

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• Anonymous
6 months ago

25 W is not a resistance.

You need to learn some electrical terminology before coming here to ask a question.

• 6 months ago

resistance is measured in Ohms,

Not Watts.If you meant Ohms, IE the coil has 25 Ohms resistancethem power expended in the coil is given by Power = V x Ior V^2 / R= 368.64 Watts

• Jim
Lv 7
6 months ago

The "units" are extremely important. Did you mean 'ohms'??

IF ohms, then:

I = V/R and Watts = I*V So Watts = V²/R

W = (96)²/25 = 368.64 w, but I would round to 370 w

• 6 months ago

how tall am i, if i am 5'6"

• 6 months ago

The resistance is 25w/96v=.260Ω

It will use 25W.

If the coil is 25Ω the the power will be 96^2/25= 387 W.

• 6 months ago

AS YOU MARKED ON QUESTION ------->>> 25W  !!!

• 6 months ago

a)

The resistance should "25 Ω" instead of "25 W".

Power of the coil consumed

= v²/R

= 96²/25

= 370 W (to 2 sig. fig.)