A small heating coil has a constant resistance of 25 W. a) How much power would the coil consume if the voltage drop across it is 96 V?

Answer 1

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Answer 2

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Answer 3

25 W is not a resistance. 

You need to learn some electrical terminology before coming here to ask a question.

Answer 4

resistance is measured in Ohms, 

Not Watts.If you meant Ohms, IE the coil has 25 Ohms resistancethem power expended in the coil is given by Power = V x Ior V^2 / R= 368.64 Watts 

Answer 5

The "units" are extremely important. Did you mean 'ohms'??

IF ohms, then:

I = V/R and Watts = I*V So Watts = V²/R

W = (96)²/25 = 368.64 w, but I would round to 370 w

Answer 6

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Answer 7

The resistance is 25w/96v=.260Ω

It will use 25W.

If the coil is 25Ω the the power will be 96^2/25= 387 W.

Answer 8

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Answer 9

a)

The resistance should "25 Ω" instead of "25 W".

Power of the coil consumed

= v²/R

= 96²/25

= 370 W (to 2 sig. fig.)