5. 2.00 L of a gas is at 740.0 mmHg pressure. What is its volume at standard pressure? ?

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  • 4 weeks ago

    PV=nRT

    at constant mole (n) and temperature 

    PV= constant(; . n,T,R are constant)

    ⇒ P1V1 = P2V2

    P1= 740mmHg              P2= 1.00 atm

    V1= 2.00 L                    V2= ?

    P1= 740/760 = 0.97 atm

    ⇒ V2 =P1V1/P2 = (0.97 atm)(2L)/(1atm)

    =1.95L

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