# 5. 2.00 L of a gas is at 740.0 mmHg pressure. What is its volume at standard pressure? ?

### 1 Answer

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- jacob sLv 74 weeks ago
PV=nRT

at constant mole (n) and temperature

PV= constant(; . n,T,R are constant)

⇒ P1V1 = P2V2

P1= 740mmHg P2= 1.00 atm

V1= 2.00 L V2= ?

P1= 740/760 = 0.97 atm

⇒ V2 =P1V1/P2 = (0.97 atm)(2L)/(1atm)

=1.95L

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