How many grams of fluorine gas occupy 543.2 mL and exert 123456 Pa of pressure at 29.8 degrees Celsius? Give answer to 3 s.f.?

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  • 1 month ago

    n = PV / RT  = 123456 Pa * 0.5432 L / 8.3144*10^3 L⋅Pa⋅K−1⋅mol−1* (273+29.8) K

    = 0.026637 moles F2

    = 0.026637 moles * 38.0 g/ mol 

    = 1.01 g F2 ( to 3 significant figures ) 😊

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