Seawater contains 7.6×10−3 g Sr2+ per kilogram of water. What is the concentration of Sr2+ measured in ppm?

2 Answers

  • 4 weeks ago

    Convert the Sr mass to mg and you then have mg Sr/kg H2O, which is ppm. 7.6 x 10^-3 g is the same as 7.6 mg, so there are 7.6 ppm (as you defined it) Sr in that water.

    If you want to see where the million comes from, convert kg to mg.  there are a million mg in one kg.  So, you have 7.6 mg Sr in 1 million mg of water.

  • Ash
    Lv 7
    4 weeks ago

    Concentration of Sr²⁺ = (7.6 x 10⁻³ g Sr²⁺)/(1 kg water)

    = 7.6 mg Sr²⁺)/(1 L water)

    = 7.6 ppm Sr²⁺

Still have questions? Get answers by asking now.