# A 2KW iron is used on a 100V AC mains. The current in the iron is?

### 9 Answers

- Anonymous4 months ago
The gurrent iz twenny ambs.

- 5 months ago
"A 2KW iron is used on a 100V AC mains. The current in the iron is?"

P=VI

I=P/I

I = 2 000/100

I= 20 Amps

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- JimLv 75 months ago
P=IE thus I = P/E

I = 2,000w/100v = 20a ←

But I question where you would ever find 100vac mains?? Did you mean 120vac as is standard in the US? then I = 2000/120 = 16.7a

- .Jerry.Lv 75 months ago
"A 2KW iron is used on a 100V AC mains. The current in the iron is?"

Assuming the supply mains are single phase, and the iron is purely resistive, then this can be answered by simple Watt's Law.

P=VI

I=P/I

I = 2 000/100

I= 20 Amps

.

- billrussell42Lv 75 months ago
P = EI

2000 watts = 100 v x I

I = 20 amps

that assumes the device is designed to draw 2 kW at 100 volts.

- nathaan27Lv 55 months ago
2,000/100 = 20 amps. P divided by E equals I. P divided by I equals E. P is the measure of power when you multiply E x I. E is electromotive force. I is current flow.