Differential equation problem ?
Verify that y = −5t cos(t) − 5t is a solution of the following initial-value problem.
t(dy/dt) = y+ 5t^(2)sin(t) y(pi)=0
y=-5cos(t)-5t ------------->(dy/dt)= ?
LHS: t(dy/dt) = t(?) = 5t^(2)sin(t) − 5t cos(t) − 5t
=? + y = RHS
please help, I don't understand this
- RealProLv 71 month ago
I don't know what trouble you are facing. You put the y(t) you are given into the differential equation you are given. Right side equals left side. y(pi) = 0. The solution is verified.
Assuming you do in fact mean y = −5t cos(t) − 5t and not y = −5 cos(t) − 5t