Sarah asked in Science & MathematicsPhysics · 5 months ago

A skateboard rolls off a horizontal ledge that is 1.12 m high, and lands 1.48 m from the base of the ledge. How much time was he in the air?

2 Answers

  • 5 months ago

    The landing distance is not a factor. Anything that drops 1.12 m on Earth, starting with zero vertical velocity and without air resistance, will take about 0.478 seconds to drop.

    1.12 = 0.5 * g * 0.478^2

  • 5 months ago

    t = √(2h/g) = √(2•1.12/9.8) = 0.478 s

    falling object starting from rest

    h is height in meters, t is time falling in seconds,

    g is acceleration of gravity, usually 9.8 m/s²

    v is velocity in m/s

    h = ½gt²

    t = √(2h/g)

    v = √(2gh)

    h = v²/2g

    v = gt

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