Mathematical formula to calculate the probability to have 3 non-consecutive heads (or 3 non-consecutive tails) in 4 tosses of a fair coin.?

How can you calculate the probability to have 3 non-consecutive heads (or 3 non-consecutive tails) in 4 tosses of a fair coin? The 3 heads (or 3 tails) should

not be consecutive, i.e. you should have 1 tail

 (or 1 head

) in the first 3 tosses.

2 Answers

Relevance
  • 3 months ago

    In four tosses, there are 16 possible outcomes. Just list them all, and count the ones that satisfy your rules.

    HHHH

    HHHT

    ...

    TTTT

  • alex
    Lv 7
    3 months ago

    Preferred outcomes

    HHTHHTHHtotal outcomes = 2^4 = 16---> P(HHTH or HTHH) = ...

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