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# Statistics. PLEASE, HELP!?

Madison has a bag with 30 red marbles and 5 green marbles. She chooses one at random. What are the odds in favor of her selecting a red marble?

P.S. The answer 6 is wrong!

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- PhilipLv 61 month ago
Total # of marbles = 30+5 = 35.;

# of red marbles = 30;

A marble is randomly selected.;

Odds of it being a red marble are (30/35) = (600/7)% = 85.7% rounded to the nearest tenth of a percent.

- formengLv 61 month ago
There seems to be some confusion about "odds" and probability.

Odds =(Probability win)/(probability lose)

=(30/35)/(5/35)

=35/5 =7:1

formeng

- Engr. RonaldLv 71 month ago
Probability of selecting red marble

P(red marble) = 30/(30 + 5) =30/35 or 6/7 or 85.7% Answer//

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- 1 month ago
There are 35 total marbles. So pulling one red marble (30) out of 35 total would be 30/35 or 0.8571 or 86%. Hope this helps!

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