Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 month ago

Statistics. PLEASE, HELP!?

Madison has a bag with 30 red marbles and 5 green marbles. She chooses one at random. What are the odds in favor of her selecting a red marble?

P.S. The answer 6 is wrong!

9 Answers

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  • Philip
    Lv 6
    1 month ago

    Total # of marbles = 30+5 = 35.;

    # of red marbles = 30;

    A marble is randomly selected.;

    Odds of it being a red marble are (30/35) = (600/7)% = 85.7% rounded to the  nearest tenth of a percent.

  • 1 month ago

    There seems to be some confusion about "odds" and probability.

    Odds =(Probability win)/(probability lose)

    =(30/35)/(5/35)

    =35/5 =7:1

    formeng

  • 1 month ago

    The probability is 30/35=6/7

  • 1 month ago

    Probability of selecting red marble

    P(red marble) = 30/(30 + 5) =30/35 or 6/7 or 85.7% Answer// 

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  • 1 month ago

    P(choose a red)=30/(30+5)=6/7.

  • 1 month ago

    There are 35 total marbles. So pulling one red marble (30) out of 35 total would be 30/35 or 0.8571 or 86%. Hope this helps!

  • 6:1 odds that she'll pick a red marble

  • ted s
    Lv 7
    1 month ago

    6 out of 7.....6/7.......86%

  • 1 month ago

    30 in 35 = 6 in 7

    or probability 6/7

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