Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 month ago

Madison has a bag with 30 red marbles and 5 green marbles. She chooses one at random. What are the odds in favor of her selecting a red marble?

P.S. The answer 6 is wrong!

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• Philip
Lv 6
1 month ago

Total # of marbles = 30+5 = 35.;

# of red marbles = 30;

A marble is randomly selected.;

Odds of it being a red marble are (30/35) = (600/7)% = 85.7% rounded to the  nearest tenth of a percent.

• 1 month ago

There seems to be some confusion about "odds" and probability.

Odds =(Probability win)/(probability lose)

=(30/35)/(5/35)

=35/5 =7:1

formeng

• 1 month ago

The probability is 30/35=6/7

• 1 month ago

Probability of selecting red marble

P(red marble) = 30/(30 + 5) =30/35 or 6/7 or 85.7% Answer//

• 1 month ago

P(choose a red)=30/(30+5)=6/7.

• 1 month ago

There are 35 total marbles. So pulling one red marble (30) out of 35 total would be 30/35 or 0.8571 or 86%. Hope this helps!

• 1 month ago

6:1 odds that she'll pick a red marble

• ted s
Lv 7
1 month ago

6 out of 7.....6/7.......86%

• 1 month ago

30 in 35 = 6 in 7

or probability 6/7