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Anonymous asked in Science & MathematicsPhysics · 1 month ago

What is values of q1 and q2? Can you help me?

In the figure two charges are fixed. Another charge Q= -1.89 μC having mass m= 4.00 g is initially at 3.00 cm from each of these two charges and released from the rest.

The initial acceleration of Q= -1.89 μC is 345 m/s^2 and upward and is parallel to the line connecting these two q1 and q2 charges. What is values of q1 and q2?

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  • 1 month ago
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    BY F = ma

    =>F = 4 x 10^-3 x 345 

    =>F = 1.38 N

    Let the forces from q1 & q2 on the Q is F1 & F2 respectively, since it is given that F1x = F2x

    =>q1 & q2 are having +ve & -ve charge, Let q1 is having +ve & q2 is having -ve charge

    Now let ∠q2q1Q = ∠q1q2Q = θ

    =>cosθ = 2.25/3 = 41.41

    =>θ = 41.418

    =>∠q1Qq2 (let 2α ) = 180 - 2 x 41.41 = 97.18*

    =>α = 48.59*

    Now Given F1x = F2x

    =>kq1Q/(3 x 10^-2)^2 xcosα =  kq2Q/(3 x 10^-2)^2 xcosα

    =>q1 = q2 = (let q)

    Thus F = F1y + F2y

    =>1.38 = [kq1Q/(3 x 10^-2)^2] x sinα + [kq1Q/(3 x 10^-2)^2] x sinα 

    =>1.38 = [2kqQ/(3 x 10^-2)^2] x sinα {as q1 = q2}

    =>1.38 = q x [{2 x 9 x 10^9 x 1.89 x 10^-12}/{9 x 10^-4}] x sin48.59*

    =>q = 48.68 x 10^-3 C

    =>q1 = +48.68 mC & q2 = -48.68 mC

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