A quantity of steam (650 g) at 119°C is condensed, and the resulting water is frozen into ice at 0°C. How much heat was removed?

I want my answer to be in kcal

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  • Ash
    Lv 7
    1 month ago

    Thermal energy removed when steam cools from 119°C to 100°C

    E₁ = m C ΔT = (0.650 kg)(1 kcal/kg°C)(119°C - 100°C) = 12.35 kcal

    Thermal energy removed when steam changes phase to water at 100 °C

    E₂ = m x Latent heat of condensation for steam = (0.650 kg)(540 kcal/kg) = 351 kcal

    Thermal energy removed when water cools from 100°C to 0°C

    E₃ = m C ΔT = (0.650 kg)(1 kcal/kg°C)(100°C - 0°C) = 65 kcal

    Thermal energy removed when water changes phase to ice at 0 °C

    E₄ = m x Latent heat of freezing for water = (0.650 kg)(80 kcal/kg) = 52 kcal

    Total heat removed = E₁ + E₂ + E₃ + E₄ = 12.35 + 351 + 65 + 52 = 480.35 kcal 

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