Anonymous

# can you please help with this question?

A basketball player makes a long pass to another player. The path of the ball can be modeled by y = −0.2x² + 2.4x + 2, where x is the horizontal distance from the player and y is the height of the ball above the court, both in meters. Determine the maximum height of the ball.

### 2 Answers

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- 1 month ago
Hi, I'll give it a try.

Max height will be when dy/dx=0 (i.e. differential)

So dy/dx= 2*(-0.2)x + 2.4 (the 2 disappears as d/dx of a constant is 0)

So -0.4x+2.4=0

get 0.4x=2.4

or x=2.4/0.4=6m

so plug x=6 into equation and see what y is

ok y=-0.2* (6^2)+2.4 *(6) +2= 9.2m

This is the same answer that Alex (the first answerer) would've have got.

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