Physics Question!!!?

A solid spherical ball (M = 14 kg; R = 30 cm) is rolling along a level surface at 25 m/s when it encounters a ramp that has a length of 15 m and is declined at an angle of 30° to the horizontal. The ball continues to roll without slipping down the ramp. Determine the magnitude of the velocity of the ball at the bottom of the ramp.

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  • NCS
    Lv 7
    4 months ago
    Favourite answer

    For a solid sphere, the moment of inertia about an axis through its center is

    I = (2/5)mR²

    "roll without slipping" means that

    ω = v/R

    so the total KE is

    KE = ½mv² + ½Iω² = ½mv² + ½*[(2/5)mR²]*(v/R)² = 0.7mv²

    final KE = initial KE + mgh

    mass m cancels

    0.7*V² = 0.7*(25m/s)² + 9.8m/s² * 15m*sin30º = 511 m²/s²

    final V = 27 m/s

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  • oubaas
    Lv 7
    4 months ago

    0,7*m*Vo*2 +  m*g*h =  0,7*m*Vf^2

    Vf = √ 0,7Vo^2/0,7+g*h/0,7 = √25^2+9,807*15*0.5/0.7 = 27.0 m/sec 

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