Physics hw help me please?
Three infinitely long wires are located at the corners of a square which has a side length of d. (d = 1mm) The wires are perpendicular to the page.
- NCSLv 71 month agoFavourite answer
B = 2e-7T·m/A * I / r
with direction given by right hand rule
AT POINT O:
r = d/√2 = 7.07e-4 m
due to I1:
B1 = 2.83e-4 T directed at NW (Θ = 135º)
due to I2:
B2 = 1.98e-3 T directed at NE (Θ = 45º)
due to I3:
B3 = 2.83e-4 T directed at SE (Θ = 45º)
B1 and B3 cancel. So the field at O is
B = B2 = 1.98e-3 T directed NorthEast
AT POINT P:
distance for I2 is d√2
magnitude due to I1 and I3:
|B1| = |B3| = 2e-7T·m/A * 1A / 0.001m = 2e-4 T
B1 is directed North and B3 is directed East.
B2 = 2e-7T·m/A * 7A / 0.001m*√2 = 9.9e-4 T
directed to Northeast
Bx = (9.9*cos45º + 2)*e-4 T = 9e-4 T
By = (9.9*sin45º + 2)*e-4 T = 9e-4 T
B = 1.4e-3 T
directed to NE (45º above "east")
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