Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 month ago

Solve the calculus a, b,  c?

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  • 1 month ago

    If you specify which of these you need help with that would make your life a lot easier.

    (c)

    y=sqrt(9-x^2) is the top half of a circle with radius 3, centered at the origin. If it says the integral from 0 to 3, then that's the area between the curve and the x-axis from x=0 to x=3.

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  • 1 month ago

    You should ask one question at a time. Better chances to get a response.

    I'll deal only with first integral

    integral (sin(x)/cos^2(x) dx) =

    substitute u=cos(x),  du= - sin(x)dx

    = integral ( - 1/u^2  du) = 1/u + C =

    substitute back u=cos(x)

    = 1/cos(x) + C

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