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# Solve the calculus a, b, c?

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- RealProLv 71 month ago
If you specify which of these you need help with that would make your life a lot easier.

(c)

y=sqrt(9-x^2) is the top half of a circle with radius 3, centered at the origin. If it says the integral from 0 to 3, then that's the area between the curve and the x-axis from x=0 to x=3.

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- SlowfingerLv 61 month ago
You should ask one question at a time. Better chances to get a response.

I'll deal only with first integral

integral (sin(x)/cos^2(x) dx) =

substitute u=cos(x), du= - sin(x)dx

= integral ( - 1/u^2 du) = 1/u + C =

substitute back u=cos(x)

= 1/cos(x) + C

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