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# find an equation of a cosine function with maximum of 7, minimum of -7 and period of 7?

find an equation of a cosine function with maximum of 7, minimum of -7 and period of 7

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- Wayne DeguManLv 71 month ago
Let y = acos(bx)

The period is 2π/b

Hence, we require that 2π/b = 7

so, b = 2π/7

Hence, y = acos(2πx/7)

Finally, -1 ≤ cos(2πx/7) ≤ 1....i.e. minimum of -1 and maximum of 1

Hence, -7 ≤ 7cos(2πx/7) ≤ 7

so, y = 7cos(2πx/7)

A sketch is below.

:)>

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- Engr. RonaldLv 71 month ago
A = [max(val) - min(val)]/2

A =[7 - (- 7)]/2

A = 7

midline = [max(val) + min(val)]/2

midline = (7 - 7)/2

midline = 0

P = 7

P = 2π/k

7 = 2π/k

7k = 2π

k = 2π/7

y = 7cos(2π/7x) Answer//

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