# Find two consecutive integers such that the smaller integer decreased by nine equals three times the larger integer.?

### 6 Answers

- ranjankarLv 74 months ago
LET THE INTEGERS BE X AND X +1

X-9 = 3 (X+1)

X-9 = 3X +3

2X = -12

X = -6

ANSWER -6 , -5

CHECK

-6-9 = -15

3* -5 = -15

- KrishnamurthyLv 74 months ago
Two consecutive integers such that the smaller integer decreased by nine equals three times the larger integer:

(x - 9) = 3(x + 1)

2x = -12

x = -6

The two consecutive integers are -6 and -5.

- Engr. RonaldLv 74 months ago
let x - smaller integer

x + 1 - larger integer

x - 9 = 3(x + 1)

x - 9 = 3x + 3

x - 3x = 3 + 9

-2x = 12

x = - 6

smaller integer is x = - 6 Answer//

larger integer = - 6 + 1 = - 5 Answer//

- Pramod KumarLv 74 months ago
Let the smaller integer = x, so that the bigger integer = x + 1

According to the given condition --

smaller decreased by 9 = x - 9

Three times the larger = 3 ( x + 1 )

Both are equal.

=> x - 9 = 3 ( x + 1 )

=>x - 9 = 3 x + 3

=> 2 x = - 12

=> x = - 6 ................ smaller Integer

=> x = - 5 .................. Larger Integer

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- la consoleLv 74 months ago
First integer: n

Consecutive integer: n + 1

…such that the smaller integer decreased by nine (n - 9) equals three times the larger integer 3.(n + 1)

n - 9 = 3.(n + 1)

n - 9 = 3n + 3

2n = - 12

n = - 6 ← first integer

n + 1 = - 5 → consecutive integer

- PhilipLv 64 months ago
Let consecutive integers be x and x+1. x-9 = 3(x+1), ie., 2x = -12, ie., x = -6. Then

x+1 = -5. Consecutive integers are -6, -9.