J asked in Science & MathematicsMathematics · 4 months ago

Find two consecutive integers such that the smaller integer decreased by nine equals three times the larger integer.?

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  • 4 months ago

    LET THE INTEGERS BE X AND X +1

    X-9 = 3 (X+1)

    X-9 = 3X +3

    2X = -12

    X = -6

    ANSWER -6 , -5

    CHECK

    -6-9 = -15

    3* -5 = -15

  • 4 months ago

    Two consecutive integers such that the smaller integer decreased by nine equals three times the larger integer:

    (x - 9) = 3(x + 1)

    2x = -12

    x = -6

    The two consecutive integers are -6 and -5.

  • 4 months ago

    let x - smaller integer

     x + 1 - larger integer

    x - 9 = 3(x + 1)

    x - 9 = 3x + 3

    x - 3x = 3 + 9

     -2x = 12

     x = - 6  

    smaller integer is x = - 6     Answer// 

    larger integer = - 6 + 1 = - 5   Answer//

  • 4 months ago

    Let the smaller integer = x,  so that  the bigger integer = x + 1

    According to the given condition --

    smaller decreased by 9  =  x - 9

    Three times the larger  =  3 ( x + 1 )

    Both are equal.

    =>  x - 9  =  3 ( x + 1 )

    =>x - 9 = 3 x + 3

    => 2 x  =  -  12

    =>  x  =  - 6   ................ smaller Integer

    =>  x  =  - 5 .................. Larger Integer

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  • 4 months ago

    First integer: n

    Consecutive integer: n + 1

    …such that the smaller integer decreased by nine (n - 9) equals three times the larger integer 3.(n + 1)

    n - 9 = 3.(n + 1)

    n - 9 = 3n + 3

    2n = - 12

    n = - 6 ← first integer

    n + 1 = - 5 → consecutive integer

  • Philip
    Lv 6
    4 months ago

    Let consecutive integers be x and x+1. x-9 = 3(x+1), ie., 2x = -12, ie., x = -6. Then

    x+1 = -5. Consecutive integers are -6, -9. 

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