J asked in Science & MathematicsMathematics · 4 months ago

# Find two consecutive integers such that the smaller integer decreased by nine equals three times the larger integer.?

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• 4 months ago

LET THE INTEGERS BE X AND X +1

X-9 = 3 (X+1)

X-9 = 3X +3

2X = -12

X = -6

ANSWER -6 , -5

CHECK

-6-9 = -15

3* -5 = -15

• 4 months ago

Two consecutive integers such that the smaller integer decreased by nine equals three times the larger integer:

(x - 9) = 3(x + 1)

2x = -12

x = -6

The two consecutive integers are -6 and -5.

• 4 months ago

let x - smaller integer

x + 1 - larger integer

x - 9 = 3(x + 1)

x - 9 = 3x + 3

x - 3x = 3 + 9

-2x = 12

x = - 6

smaller integer is x = - 6     Answer//

larger integer = - 6 + 1 = - 5   Answer//

• 4 months ago

Let the smaller integer = x,  so that  the bigger integer = x + 1

According to the given condition --

smaller decreased by 9  =  x - 9

Three times the larger  =  3 ( x + 1 )

Both are equal.

=>  x - 9  =  3 ( x + 1 )

=>x - 9 = 3 x + 3

=> 2 x  =  -  12

=>  x  =  - 6   ................ smaller Integer

=>  x  =  - 5 .................. Larger Integer

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• 4 months ago

First integer: n

Consecutive integer: n + 1

…such that the smaller integer decreased by nine (n - 9) equals three times the larger integer 3.(n + 1)

n - 9 = 3.(n + 1)

n - 9 = 3n + 3

2n = - 12

n = - 6 ← first integer

n + 1 = - 5 → consecutive integer

• Philip
Lv 6
4 months ago

Let consecutive integers be x and x+1. x-9 = 3(x+1), ie., 2x = -12, ie., x = -6. Then

x+1 = -5. Consecutive integers are -6, -9.

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