J asked in Science & MathematicsMathematics · 4 months ago

The perimeter of a rectangle is 312 meters. If the length is six meters more than five times the width what are the length and the width?

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  • 4 months ago

    PERIMETER = 2 ( LENGTH + WIDTH )= 312

    LENGTH + WIDTH = 312/2 = 156

    LET THE WIDTH BE  X

    LENGTH = 5X +6

    5X +6 +X = 156

    6X= 150

    X = 25

    ANSWER WIDTH = 25m   length = 131m

  • 4 months ago

     The perimeter of a rectangle is 312 meters. 

     If the length is six meters more than five times the width 

     what are the length and the width?

     l + w = 156 

     5w + w = 150 

     w = 25

     The length of the rectangle is 131 meters and 

     the width is 25 meters.

  • 4 months ago

    Given 

    P = 312

    l = 5w + 6

    P = 2l + 2w

    312 = 2(5w + 6) + 2w

    312 = 10w + 12 + 2w

    312 = 12w + 12

    312 - 12 = 12w

    300 = 12w

    w = 25 m Answer//

    l = 5w  + 6 = 5(25) + 6 = 131 m Answer//

    Therefore, the length is 131 m,  and width is 25 m

  • 4 months ago

    ℓ: length of the rectangle

    ω: width of the rectangle

    The perimeter of the rectangle is:

    p = 2.(ℓ + ω) → given that it's 312 m

    2.(ℓ + ω) = 312

    ℓ + ω = 156 → the length is 6 m more than five times the width: ℓ = 5ω + 6

    5ω + 6 + ω = 156

    6ω = 150

    → ω = 25 m

    Recall: ℓ = 5ω + 6

    ℓ = (5 * 25) + 6

    → ℓ = 131 m

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  • Bill-M
    Lv 7
    4 months ago

    312 = 2X + 2 ( 5X+6)      Perimeter =  2 times the Width + 2 times the Length.

    312 = 2X + 10X + 12

    312 = 12X + 12

    300 = 12 X

    X = 300/12

    Width = 300/12

    You can do the rest.

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