Anonymous
Anonymous asked in Science & MathematicsChemistry · 1 month ago

What mass of NaHCO3 would he need to ingest to neutralize this much HCl?

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  • Ash
    Lv 7
    1 month ago

    moles of HCL = 0.081 M HCL x 0.100 L = 0.0081 moles

    From balanced equation moles of NaHCO3 required to neutalize are same as HCl, so

    moles of NaHCO3 = 0.0081 moles

    mass of NaHCO3 = moles  of NaHCO3 x molar mass of NaHCO3 

    mass of NaHCO3 = 0.0081 moles x 84.007 g/mol = 0.68 g

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