What mass of NaHCO3 would he need to ingest to neutralize this much HCl?
- AshLv 71 month ago
moles of HCL = 0.081 M HCL x 0.100 L = 0.0081 moles
From balanced equation moles of NaHCO3 required to neutalize are same as HCl, so
moles of NaHCO3 = 0.0081 moles
mass of NaHCO3 = moles of NaHCO3 x molar mass of NaHCO3
mass of NaHCO3 = 0.0081 moles x 84.007 g/mol = 0.68 g