magnetic field?

A rectangular loop of wire crossed by a current of 2 A is suspended vertically e

attached to the right plate of a scale. When the system is balanced, it is introduced into

an external magnetic field. The field acts only in the lower part of the coil in

direction perpendicular to the side of the loop. Knowing that the coil is 20 cm wide and it is

it is necessary to add a mass of 13.5 g on the left pan of the scale to balance

the system, determine B

1 Answer

  • 4 months ago
    Favourite answer

    By F = iLBsinθ

    =>mg = iLBsinθ

    =>13.5 x 10^-3 x 9.8 = 2 x 20 x 10^-2 x B x sin90*

    =>B = 0.33 T

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