# For the following right triangle, find the side x length .? Relevance
• The Pythagorean theorem for the right angle triangle is

(Hypotenuse)^2 = (Base)^2 + (Perpendicular)^2

x^2 = 24^2 + 7^2

x^2 = 576+49

x^2 = 625

By taking square root on both sides, we get the value of x

x = 25

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•  You can solve that equation by the Pythagorean Theorem: a^2 + b^2 = c^2. The letter "c" is what you are trying to solve. We can replace that with "x" to make it easier.

Plug in the numbers: 7^2 + 24^2 = x^2

49 + 576 = x^2

625 = x^2

In order to find "x", take the square root of 625, which is equal to 25.

Therefore, side "x" is equal to 25.

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• X=sqrt(24*24+7*7)=sqrt(625)=  25

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• The square root of (24squared + 7squared)

In a Right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides (adjacent and opposite)

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• Quickest way, take the shortest. 7

7 x 7 = 49 minus 24 is 25

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• = (7^2 + 24^2)^(1/2) = 25

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• x = (7^2 + 24^2)^(1/2) = 25

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• Apply Pythagorean theorem

x = √(a^2 + b^2)

x =  √(7^2 + 24^2)

x =√(625)

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• use Pythagorean theorem

a^2+b^2=c^2

or

7^2+24^2=x^2

then solve

576+49=x^2

625=x^2

therefore x=25

I hope this helps

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• x^2 = 24^2 + 7^2

x^2 = 576 + 49

x^2 = 625

x = 25

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