F asked in Science & MathematicsChemistry · 9 months ago

rate of formation of bromine ∆[Br2 ]/∆t, is 6.0 x 10-6 M/s What is the rate of consumption of H+ , ∆[H^+ ]/∆t? 5Br−+BrO3−+6H+⟶3Br2 +3H2O?

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  • Dr W
    Lv 7
    9 months ago

    6.0x10^-6 M/s Br2 * (6 H+ / 3 Br2) = 1.2x10^-5 M/s H+

  • 9 months ago

    5 Br{-} + BrO3{-} + 6 H{+} ⟶ 3 Br2 + 3 H2O

    (6.0 x 10^-6 M/s) x (6 mol H{+} / 3 mol Br2) = - 1.2 x 10^-5 M/s H{+}

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