A 50.0-g copper calorimeter contains 240 g of water at 20.0°C. How much steam at 100°C must be condensed into the water if the final temperature of the system is to reach 60.0°C?
- NCSLv 72 months ago
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The answer depends on what you take as the specific heat of water and copper, and the heat of vaporization of water.
spec heat copper c = 0.385 J/g·ºC
spec heat water c = 4.186 J/g·ºC
heat of vap water L = 2256 J/g·ºC
If you have different values in your references, use them.
heat given up by steam = heat gained by water and cup
copper mass * (L + c*ΔT) = (water + copper)*ΔT
m * (2256 + 4.186*40) = (240*4.186 + 50.0*0.385)*40
for m the mass of steam in grams
m = 10537 / 2423 = 4.35 g
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