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Anonymous
Anonymous asked in Science & MathematicsMathematics · 2 months ago

Math question?

In how many ways one can arrange 2 identical history books, 3 identical physics books, and 5 identical math books?

Update:

Combinatorics question

3 Answers

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  • 2 months ago
    Favourite answer

    If they were 10 distinguishable books, then there would be 10! permutations. But we need to divide by 2!, 3! and 5! to account for the arrangements of each book subject that would be indistinguishable.

    10! / (2! 3! 5!) = 2520 ways

    • asking2 months agoReport

      I'm not op, but can i ask why that is? i just saw the question and was interested.

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  • Bill-M
    Lv 7
    2 months ago

    That is 10 books total.   10!   (10 Factorial). = 3628800

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  • 2 months ago

    1 - unless you have OCD and keep moving them around.

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