When methanol, CH 3 OH , is burned in the presence of oxygen gas, O 2 , a large amount of heat energy is released.?
When methanol, CH3OH,is burned in the presence of oxygen gas, O2,a large amount of heat energy is released. For this reason, it is often used as a fuel in high performance racing cars. The combustion of methanol has the balanced, thermochemical equation
CH 3 OH ( g ) + 3 2 O 2 ( g ) ⟶ CO 2 ( g ) + 2 H 2 O ( l ) Δ H = − 764 kJ
How much methanol, in grams, must be burned to produce 865 kJ of heat?
- anonymousLv 72 months agoFavourite answer
(865 kJ) x (1 mole CH₃OH / 764 kJ) x (32.04 g CH₃OH / 1 mole CH₃OH)
= 36.3 g CH₃OH ….. to 3 sig figs