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CHEMISTRY HELP ?

Using the following equation for the combustion of octane, calculate the heat of reaction for 75.00 g of octane. The molar mass of octane is 114.33 g/mole.

2 C8H18 + 25 O2 → 16 CO2 + 18 H2O ΔH°rxn = -11018 kJ

-7230 kJ

+4200 kJ

-3615 kJ

+3.615 kJ

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  • 2 months ago

    2 C₈H₁₈ + 25 O₂ → 16 CO₂ + 18 H₂O … ΔH°rxn = -11018 kJ

    Heat of reaction for each mole of C₈H₁₈ = (-11018 kJ) / (2 mol) = -5509 kJ/mol

    Moles of C₈H₁₈ = (75.00 g) / (114.33 g/mol) = 0.6560 mol

    Heat of reaction for 55g of C₈H₁₈ = (-5509 kJ/mol) × (0.6560 mol) = -3614 kJ

    The closest answer: -3615 kJ

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