Nonuniform circular motion/fricton?
A toy train rolls around a horizontal 1.0 m diameter track. The coefficient of rolling friction is 0.10. How long does it take the train to stop if it's released with an angular speed of 26 rpm?
- billrussell42Lv 72 months ago
1 rev = πd = 3.14 m
26 rev/min x 3.14 m/rev x 1min/60s = 1.36 m/s
force of friction = 0.1w = 0.1mg = 0.98m
de-acceleration = F/m = 0.98m/m = 0.98 m/s²
"How long" ? is that time or distance? assuming time
v = v₀ + at
0 = 1.36 + (–0.98)t
t = 1.39 s