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Jenny asked in Science & MathematicsPhysics · 2 months ago

Nonuniform circular motion/fricton?

A toy train rolls around a horizontal 1.0 m diameter track. The coefficient of rolling friction is 0.10. How long does it take the train to stop if it's released with an angular speed of 26 rpm?

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  • 2 months ago

    1 rev = πd = 3.14 m

    26 rev/min x 3.14 m/rev x 1min/60s = 1.36 m/s

    force of friction = 0.1w = 0.1mg = 0.98m

    de-acceleration = F/m = 0.98m/m = 0.98 m/s²

    "How long" ? is that time or distance? assuming time

    v = v₀ + at

    0 = 1.36 + (–0.98)t

    t = 1.39 s

    • Jenny2 months agoReport

      Yes, "how long" is time! Thank you for your help! :)

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