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a student starts at {0,0} and walks to {6,0} turns right and walks to {6,8} what is the total distance the student walked?

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  • 2 months ago

    6 units forwards and 8 units backwards...

     Or an infinite distance, down to negative infinity, coming back down from positive infinity. 

    Or he turned left at (6,0)

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  • 2 months ago

    14..........................

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  • 2 months ago

    The student should turn left at (6,0). To show a point we conventionally use (x,y)

    known as the ordered pair, not {x,y} unless you define it & show its exact meaning.

    The total distance=6+8=14.

    • ...Show all comments
    • Pinkgreen
      Lv 7
      2 months agoReport

      Even now, "#2 There are scores of newbies on here that do not even try." & "Homework Ain't Us.". They seemed 
      some " extraordinary language"! If I were you, I would
      write " why didn't you draw a picture on a piece of graph
      paper & then add 8 to 6." instead of that of yours.

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  • 2 months ago

    A student starts at {0, 0} and walks to {6, 0} 

    turns left (not right) and walks to {6, 8}. 

    The total distance the student walked is 14 units.

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  • 2 months ago

    Hi, I'm wondering if you copied this question exactly as it appeared in the source.

    There are two possibilities here:

    1) How far did he/she walk? He walked 6 units in the x-direction; then i units in the y-direction for a total of 14 units.

    2) What distance is he/she from the starting point? This is a right triangle with sides 6 and 8. So, you use the Pythagorean theorem to find the hypotenuse:

    sqrt(6^2 +8^2) =10 units.

    Hope this helps.

    formeng 

    • Pinkgreen
      Lv 7
      2 months agoReport

      The total distance should be 14; the displacement is 10.
      One must make clear that. Thus the answer=14.

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  • RR
    Lv 7
    2 months ago

    (0,0) to (6,0)

    He walks 6 in the x coordinate and 0 in the y coordinate

    (6,0) to (6,8)

    He walks 0 in the x coordinate and 8 in the y coordinate

    6 + 8 = 14

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  • ted s
    Lv 7
    2 months ago

    walked 14 but is only 10 units from the starting point

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  • 2 months ago

    They went right 6 units. Then they went up 8 units.

    You asked for the total distance the student walked which would just be the sum.

    6 + 8 = 14 units

    However, perhaps you meant to ask, how far they are from their starting point. If you imagine a right triangle, one leg would be 6 and the other would be 8. The hypotenuse would be the distance between the origin and the final point.

    Use the Pythagorean Theorem:

    6² + 8² = c²

    36 + 64 = c²

    c² = 100

    c = √100

    c = 10

    Answer:

    14 units walking and now they are 10 units from their starting point.

    • SumDude
      Lv 7
      2 months agoReport

      Shh (!) Do not confuse her with the 3-4-5 (and multiples) Pythagorean right triangle and formula. {CV isolation is getting to me.} // regards

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  • 2 months ago

    apply distance formula

    d1 = √[(6 - 0)^2 + (0 - 0)^2] = 6 units

    d2 = √[(6 - 6)^2 + (8 - 0)^2] = 8 units

    total distance = d1 + d2 = 6 + 8 = 14 units  answer//

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  • 2 months ago

    distance between (0, 0) and (6, 0) is 6 units

    distance between (6, 0) and (6, 8) is 8 units

    total distance = 6 + 8 = 14 units

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